Answer:
[tex]1.7137\ \text{mg/L}[/tex]
Explanation:
Chlorine gas available = 27 lbs = [tex]27\times 453.59237=12247\ \text{g}[/tex]
Amount of water used each day = 750000 gal = [tex]750000\times3.785411784=2839058.84\ \text{L}[/tex]
Rate at which chlorine gas used = 2.6 mg/L
Chlorine gas used
[tex]2839058.84\times 2.6\times 10^{-3}=7381.55\ \text{g}[/tex]
Residual content of chlorine = [tex]12247-7381.55=4865.45\ \text{g}[/tex]
Concentration of the residual chlorine is given by
[tex]\dfrac{4865.45}{2839058.84}=0.0017137\ \text{g/L}=1.7137\ \text{mg/L}[/tex]
Concentration of the residual chlorine is [tex]1.7137\ \text{mg/L}[/tex].
