Answer:
f⁻¹(x) = 2x - 8
f⁻¹(4) = 2 × 4 - 8
f⁻¹(4) = 0
Step-by-step explanation:
[tex]f(x) = \frac{1}{2} x + 4\\x = \frac{1}{2} f^{-1}(x) + 4\\x - 4 = \frac{1}{2} f^{-1}(x)\\2x - 8 = f^{-1}(x)\\f^{-1}(x) = 2x - 8[/tex]
Let's test it
[tex]f^{-1}(f(x)) = 2(f(x)) - 8\\f^{-1}(f(x)) = 2( \frac{1}{2}x + 4) - 8\\f^{-1}(f(x)) = \frac{2}{2}x + 8 - 8\\f^{-1}(f(x)) = x[/tex]
So we do indeed have the inverse function, so using that we can plug in the values requested:
f⁻¹(x) = 2x - 8
f⁻¹(4) = 2 × 4 - 8
f⁻¹(4) = 0
Answers:
The inverse function is ƒ ^-1 (x)= 2x-8
The value of ƒ ^-1 (4)= 0
Hope this helps <3
