Answer:
[tex]d \approx 12.6[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Algebra II
- Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
Point (-4, -6)
Point (8, -10)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
- Substitute [DF]: [tex]d = \sqrt{(8+4)^2+(-10+6)^2}[/tex]
- Add: [tex]d = \sqrt{(12)^2+(-4)^2}[/tex]
- Exponents: [tex]d = \sqrt{144+16}[/tex]
- Add: [tex]d = \sqrt{160}[/tex]
- Simplify: [tex]d = 4\sqrt{10}[/tex]
- Evaluate: [tex]d = 12.6491[/tex]
- Round: [tex]d \approx 12.6[/tex]
