First you must determing the formulas of both of the compounds
Tin (II) Chloride
the (II) means that Tin is 2+ in this compounds; and we know that Cl is -
So the formula for Tin (II) Chloride has to be
SnCl₂
For Sodium Sulfide we know that Sodium is + and Sulfide Ions are 2- so the formula for Sodium Sulfide has to be
Na₂S
As of right now our equation is
SnCl₂ + Na₂S →
When these two compounds react they will form Sodium Chloride and Tin Sulfide
The equations for the two products will be
NaCl and SnS
now our equation looks like this
SnCl₂ (aq) + Na₂S (aq) → NaCl + SnS
for this to be complete however, we need to first add phases to each of the products and balance the equation
We know that all Group one elements are soluble in water so this means NaCl is soluble
SnCl₂ (aq) + Na₂S (aq) → NaCl (aq) + SnS
we also know that all sulfides are insoluble which means SnS is insoluble
SnCl₂ (aq) + Na₂S (aq) → NaCl (aq) + SnS (s)
Now that we have the phases written in we must balance the equation
There is 1 Sn, 2Cl, 2 Na and 1 S on the left/reactants side
and 1 Na, 1 Cl, 1Sn, and 1S on the right/products side
to balance it we need to have 2 Cl on the right hand or products side
SnCl₂ (aq) + Na₂S (aq) → 2 NaCl (aq) + SnS
Now everything is balanced!
SnCl₂ (aq) + Na₂S (aq) → 2 NaCl (aq) + SnS is our final reaction equation
