Step-by-step explanation:
Let (x, y) be the coordinates of point B.
(4, 6) => (-2, 4) => (x, y)
We have 2(-2) = 4 + x and 2(4) = 6 + y.
Solving these, we get x = -8 and y = 2.
Hence the coordinates of point B is (-8, 2).
Point Q is the midpoint of AB. Q has coordinates of (-2, 4) and A has coordinates of (4,6). Hence the coordinates of point B will be (-8, 2).
Suppose we've two endpoints of a line segment as:
A (p,q), and B (m,n)
Then let the midpoint be M(x,y) on that line segment.
Then, its coordinates are:
[tex]x = \dfrac{p+m}{2}[/tex]
and
[tex]y = \dfrac{q+n}{2}[/tex]
Let (x, y) be the coordinates of point B.
Q has coordinates of (-2, 4).
A has coordinates of (4,6).
A (p,q) = (4, 6)
M(x,y)= (-2, 4)
B = (x, y)
We have
2(-2) = 4 + x
2(4) = 6 + y.
Solving these, we get
x = -8 and y = 2.
Hence the coordinates of point B will be (-8, 2).
Learn more about midpoint here;
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