The temperature of a pot of water was 180.3°F and cools at a rate of -2.5°F per minute. a. What is the temperature after 20 minutes? b. Look for Relationships How many minutes will it take to cool from 180.3°F to 100.3°F?

Respuesta :

Answer:

130.3

32

Step-by-step explanation:

Answer:

A. 130.3F B. 32 minuits

Step-by-step explanation:

A: if It cools 2.5F a minuite than we will do 20x2.5=50

180.3-50=130.3

B: 180.3-100-3=80. So that means it cooled 80 degrees. we then divide 80 by 2.5. 80/2.5=32. and we know that it has cooled for 32 minuits