Respuesta :

9514 1404 393

Answer:

  -1.317

Step-by-step explanation:

  [tex]\log_5{15}=x+3 \qquad\text{given}\\\\ \dfrac{\log{15}}{\log{5}}=x+3 \qquad\text{change of base formula}\\\\x=\dfrac{\log{15}}{\log{5}}-3 \qquad\text{subtract 3}\\\\x\approx\dfrac{1.17609}{0.69897}-3\approx 1.683 -3\\\\ \boxed{x\approx -1.317}[/tex]

Answer:

-1.317

Step-by-step explanation:

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