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For a moving object, the force acting on the object where is directly from the objects acceleration. When a force of 21 N Acts on a certain object, the acceleration of the object is 7 m/s^2. If the acceleration of the object becomes 9 m/s^2, what is the force?

Respuesta :

MrRoyal

Answer:

[tex]F = 27N[/tex]

Step-by-step explanation:

Given

Force directly proportional to acceleration

Force = 21N when Acceleraion = 7m/s^2

Required

Determine the force when acceleration = 9m/s^2

The variation between force (F) and acceleration (A) implies that:

[tex]F\ \alpha\ \ A[/tex]

Convert to an equation

[tex]F = mA[/tex]

Where m is constant.

When F = 21 and A = 7, we have:

[tex]21 = m * 7[/tex]

Solve for m

[tex]m = \frac{21}{7}[/tex]

[tex]m = 3[/tex]

When A = 9

Substitute 9 for A and 3 for m in [tex]F = mA[/tex]

[tex]F = 3 * 9[/tex]

[tex]F = 27N[/tex]

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