Answer:
(i) ∠ABH = 14.46⁰
(ii) The length of AH = 4.6 m
Step-by-step explanation:
From the image uploaded;
Consider △ABC;
the length of b is calculated by applying Pythagoras theorem as follows;
b² = c² - a²
b² = (13.2)² - (6.9)²
b² = 126.63
b = √126.63
b = 11.25 m
Also, ∠ABC is calculated as;
[tex]Cos \ B = \frac{a^2+c^2-b^2}{2ac} \\\\Cos \ B = \frac{(6.9)^2+(13.2)^2-(11.25)^2}{2(6.9 \times13.2)}\\\\ Cos \ B = \frac{95.288}{182.16} \\\\ Cos \ B = 0.5219 \\\\B = Cos ^{-1} (0.5231)\\\\B = 58.46 ^o[/tex]
Consider △CBH, ∠CBH is calculated as;
∠CBH = 90⁰ - 46⁰ = 44⁰
(i) ∠ABH will be calculated as;
∠ABH = θ
θ + 44⁰ = ∠ABC
θ + 44⁰ = 58.46⁰
θ = 58.46⁰ - 44⁰
θ = 14.46⁰
Thus, ∠ABH = 14.46⁰
(ii) The length of AH
length HC is calculated as;
[tex]tan \ 46^o =\frac{6.9}{HC} \\\\HC = \frac{6.9}{tan \ 46^o } \\\\HC = 6.66 \ m[/tex]
length of AH = CA - HC
x = b - HC
x = 11.25 - 6.66
x = 4.6 m
length of AH = 4.6 m
