Answer:
94.74 moles of NO₂ are produced.
Explanation:
Given data:
Volume of oxygen gas = 3714 L
Temperature = 273 K
Pressure = 1 atm
Moles of NO₂ produced = ?
Solution:
Chemical equation:
4NH₃ + 7O₂ → 4NO₂ + 6H₂O
Number of moles of oxygen:
At STP one mole of any gas occupy 22.4 L volume. Thus, 3714 L gas contain,
3714 L× 1 mol / 22.4 L
165.8 mol
now we will compare the moles of oxygen and nitrogen dioxide.
O₂ : NO₂
7 : 4
165.8 : 4/7×165.8 = 94.74 mol
Thus, 94.74 moles of NO₂ are produced.
