jakefastf jakefastf

24-12-2020
Chemistry

contestada

what volume (in L) of a 3.95 M potassium chloride solution would be needed to make 325 mL of a 2.76 M solution by dilution

Respuesta :

ChoiSungHyun ChoiSungHyun

24-12-2020

Explanation:

Moles of KCl in new solution = 0.325dm³ * (2.76mol/dm³) = 0.897mol.

Hence volume needed = 0.897mol / (3.95mol/dm³) = 0.227dm³ or 0.227L.

Answer Link

xenapin808 xenapin808

25-02-2021

Answer:

0.227 L

Explanation:

Answer Link

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