Answer:
The boiling point of the liquid it 210.25°F
Step-by-step explanation:
Linear Modeling
Some real-life events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to build the model and predict unknown behaviors.
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
[tex]\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
We are given the following points (H,A) where A is the altitude and P is the boiling point of a certain liquid: (8200,199.42) and (4700,206.07)
Applying the formula:
[tex]\displaystyle B-199.42=\frac{206.07-199.42}{4700-8200}(A-8200)[/tex]
Calculating:
[tex]\displaystyle B-199.42=\frac{6.65}{-3500}(A-8200)[/tex]
[tex]\displaystyle B-199.42=-0.0019(A-8200)[/tex]
[tex]\displaystyle B-199.42=-0.0019A+15.58[/tex]
[tex]\displaystyle B=-0.0019A+15.58+199.42[/tex]
The equation is:
[tex]\displaystyle B=-0.0019A+215[/tex]
Finally, we calculate the boiling point at A=2500 ft:
\displaystyle B=-0.0019*2500+215
B = 210.25°F
The boiling point of the liquid it 210.25°F
