Blake is working two summer jobs, making $9 per hour washing cars and making $22 per hour tutoring. In a given week, he can work no more than 16 total hours and must earn no less than $220. If x represents the number of hours washing cars and y represents the number of hours tutoring, write and solve a system of inequalities graphically and determine one possible solution.

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Answer:

9x + 22y ≥ 220

x + y ≤ 16

Step-by-step explanation:

First x is number of hours washing cars and y is number of hours tutoring.

He makes $9 per hour on cars, $22 per hour tutoring. So we use variables as substitutes for actual values.

That is 9x + 22y. He can't make less than 220, so use the sign greater or equal to 220.

He also must work no more than 16 hours. Total hours is x+y, and no more than 16 means use the sign less than or equal to.

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Answer:

Variable Definitions

x=

x=

\,\,\text{the number of hours washing cars}

the number of hours washing cars

y=

y=

\,\,\text{the number of hours tutoring}

the number of hours tutoring

\text{\textquotedblleft no more than 16 hours"}\rightarrow \text{16 or fewer hours}

“no more than 16 hours"→16 or fewer hours

Therefore the total number of hours worked in both jobs, x+yx+y, must be less than or equal to 16:16:

x+y\le 16

x+y≤16

no less than $220"$220 or more

“no less than $220"→$220 or more

Blake makes $9 per hour washing cars, so in xx hours he will make 9x9x dollars. Blake makes $22 per hour tutoring, so in yy hours he will make 22y22y dollars. The total amount earned 9x+22y9x+22y must be greater than or equal to \$220:$220:

9x+22y\ge 220

9x+22y≥220

\text{Solve each inequality for }y\text{:}

Solve each inequality for y:

\begin{aligned}x+y\le 16\hspace{30px}& 9x+22y\ge 220 \\[0.8em] y\le 16-x \hspace{30px}& 22y\ge 220-9x \\[0.8em] \hspace{30px}& y\ge \frac{220-9x}{22} \\[0.8em] & y\ge 10-\frac{9}{22}x\end{aligned}

x+y≤16

y≤16−x

9x+22y≥220

22y≥220−9x

y≥

22

220−9x

y≥10−

22

9

x

Graph

Step-by-step explanation:

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