Given:
Inter quartile range(IQR) of a distribution = 7
25th percentile = 16
To find:
The upper quartile.
Solution:
We have,
IQR = 7
25th percentile = lower quartile = 16
We know that,
IQR = Upper quartile - Lower quartile
Let the upper quartile be [tex]Q_3[/tex].
Using the above formula, we get
[tex]7=Q_3-16[/tex]
Adding 16 on both sides, we get
[tex]7+16=Q_3-16+16[/tex]
[tex]23=Q_3[/tex]
Therefore, the upper quartile of the distribution is 23.