Answer:
Work done = 4 J
Final Kinetic Energy = 4 J
Explanation:
From the question,
Work done = force × distance
W = F×d................... Equation 1
Given: F = 4.0 N, d = 1.0 meter.
Substitute these values into equation 1
W = 4×1
W = 4 Joules.
Also,
Kenetic Energy = 1/2 × mass × velocity×velocity.
K.E = 1/2(mv²)........... (2).
But,
F = ma
Where F = 4 N, m = 1 kg.
a = 4/1 = 4 m/s².
Using,
v² = u² + 2as............. Equation 3
Where u = 0 m/s, a = 4 m/s², s = 1 m.
Substitute into equation 3
v² = 0² +2×4×1
v² = 8
v = √8 m/s.
Substitutting into equation 2
K.E = 1/2(1)(√8)²
K.E = 1/2(8)
K.E = 4 J.
Hence the work done and the Final Kinetic energy are thesame = 4 J
The work done by the Pete is 4.0 J. And its final velocity and kinetic energy are 2.82 m/s and 3.97 J respectively.
Given data:
The force applied by the Pete Zaria is, F = 4.0 N.
The mass of mud is, m = 1.0 kg.
The distance of the countertop is, s = 1.0 m.
The work by the Pete on the mug is equal to the product of applied force and the distance covered by the mug along the rooftop. Therefore,
W = F × s
W = 4.0 × 1.0
W = 4.0 J
Now, apply the third kinematic equation of motion to obtain the final velocity of the mug as,
[tex]v^{2} = u^{2}+2as[/tex]
Here, a is the magnitude of acceleration and its value is,
F = ma
4.0 = (1.0)a
a = 4.0 m/s²
Now,
[tex]v=\sqrt{0^{2}+(2 \times 4 \times 1)}\\\\v = 2.82 \;\rm m/s[/tex]
Now. the kinetic energy of the mug is calculated as,
[tex]KE = \dfrac{1}{2}mv^{2}\\\\KE = \dfrac{1}{2} \times 1.0 \times 2.82^{2}\\\\KE = 3.97 \;\rm J[/tex]
Thus, we can conclude that the work done by the Pete is 4.0 J. And its final velocity and kinetic energy are 2.82 m/s and 3.97 J respectively.
Learn more about the kinetic energy here:
https://brainly.com/question/17858145
