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A political candidate wanted to understand what issues were important to their voters. They asked 1,999 voters, "Which issue is the most important: crime, city planning, or health care?" The results of the survey are shown in the two-way table below:
Crime City Planning Health Care
Male 118 239 458
Female 418 317 449


How many percent is the chance that a person chosen at random from this survey is concerned about crime, given that they are male? Round your answer to the nearest tenth.
A. 5.9% B. 14.5% C. 22.0% D. 26.8%

Respuesta :

scme1702
This event can be broken down into two sub-event. 
1) The person selected is male
AND
2) The person feels that crime is the biggest problem
The probability of 1:
(118 + 239 + 458)/1999
= 0.4077
The probability of 2:
118/815
= 0.1448
Probability of both occurring:
0.4077 * 0.1448
= 0.0590
= 5.9%
The answer is A

The chance that a person chosen at random from this survey is concerned about crime, given that they are male is; B: 14.5%

How to find the percentage?

Let M be the event of choosing a person that is male.

Let C be the event of choosing a male who is concerned about crime.

From the given table, the number of males concerned about crime = 118

Thus, the probability of choosing a person that is male is;

P(C) = 118/1999

The number of males surveyed = 118  + 239 + 458 = 815

Thus;

P(M) = 815/1999

Now, the probability that a person chosen at random from this survey is concerned about crime, given that they are male is given by:

P(C|M) = P(C)/P(M)

P(C|M) = (118/1999)/(815/1999)

P(C|M) = 0.145 = 14.5%

Read more about Percentages at; https://brainly.com/question/843074

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