Answer:
This question is incomplete as it lacks the number of moles of Bromine. The complete part is as follows: 0.0900 moles of bromine liquid participate in a chemical reaction.
The answer is 7.191g
Explanation:
The number of moles in a substance can be calculated thus;
moles = mass/molar mass
Atomic mass of Bromine = 79.9g/mol
According to the question, the chemist determines by measurements that 0.0900 moles of bromine liquid participate in a chemical reaction. To calculate the mass of bromine liquid that participates, we say;
Mass = moles × molar mass
Mass = 0.0900 × 79.9
Mass = 7.191g
Therefore, 7.191g of Bromine will participate in the chemical reaction.
