Answer:
95% of confidence intervals are
(197.706 , 198.294)
Step-by-step explanation:
Explanation:-
Given sample size 'n'=100
Mean of the sample x⁻ = 198
The standard deviation of the Americans =15
95% of confidence intervals are determined by
[tex](x^{-} - Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} })[/tex]
Level of significance = 0.05
Z₀.₀₅ = 1.96
= [tex](198 - 1.96 \frac{15}{\sqrt{100} } , 198 +1.96\frac{15}{\sqrt{100} })[/tex]
= ( 198 -0.294 ,198 +0.294)
= (197.706 , 198.294)
95% of confidence intervals are
(197.706 , 198.294)