What needs to be done to rationalize the expression 5 over 2 minus radical 3 so there will no longer be a radical in the denominator

Respuesta :

Answer:

[tex]10+5\sqrt{3}[/tex]

Step-by-step explanation:

Given the expression: 5 / (2 - √3)

To rationalize the denominator, we multiply the numerator and denominator by the conjugate of the denominator. The conjugate of (2 - √3) is (2 + √3). Hence multiplying gives:

[tex]\frac{5}{2-\sqrt{3} }*\frac{2+\sqrt{3}}{2+\sqrt{3}} \\\\=\frac{10+5\sqrt{3} }{4+2\sqrt{3}-2\sqrt{3}-3 }\\\\Simplifying\ the\ expression:\\\\ =\frac{10+5\sqrt{3} }{1}\\\\= 10+5\sqrt{3}[/tex]

Hence: 5 / (2 - √3) = [tex]10+5\sqrt{3}[/tex]