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the present ages of two brothers are 15 years and 22 years respectively after how many years will the product of their ages be 408​

Respuesta :

ChoiSungHyun

Step-by-step explanation:

Let (15 + x) and (22 + x) be the future ages of the brothers.

We have (15 + x)(22 + x) = 330 + 37x + x² = 408

Therefore x² + 37x = 78 and x = 2.

Hence the answer is 2 years later.

choccocakee
Let (15+x) and (22+x) be the future ages of the brothers


15+x+22+x= 408

Collect like terms

37+2x=408

Move 37 to the other side as a negative number


2x=371

Divide both sides by 2


371/2 is 185.5

So, after 185.5 years, their ages will add up to be 408

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