Answer:
Standard error (S.E) = 0.048 ≅ 0.05
Step-by-step explanation:
Explanation:-
Given sample size 'n'=76
Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.
Sample proportion
[tex]p = \frac{x}{n} = \frac{58}{76} = 0.7631[/tex]
The standard error is determined by
[tex]S.E = \sqrt{\frac{p(1-p)}{n} }[/tex]
[tex]S.E = \sqrt{\frac{0.763(0.2369}{76} }[/tex]
Standard error is 0.048 ≅ 0.05