A car of weight 11000 N moves with constant velocity along a horizontal road.A driving force of 5000 N acts on the car what is the force opposing the motion of the car

Respuesta :

Answer:

5000 N

Explanation:

Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.

Since the car is moving with constant velocity, a = 0.

So, F - f = ma

F - f = m(0)

F - f = 0

F = f.

Since F = 5000 N and F = f, f = 5000 N.

So, the opposing force is 5000 N

The opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.

The opposing force can be calculated by the formula,

F - f = ma

Where,

F = driving force = 5000 N,

f = opposing force = ?

m = mass of car = 11000 N

a = acceleration of car

Since, the car is at constant velocity, a = 0.

So,

F - f = m(0)

F - f = 0

F = f.

Therefore, the opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.

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