Answer:
The best order size to minimize cost will be 5,000
They will produce for 10 days in a row.
Explanation:
D = annual demand 25,000
S= setup cost = ordering cost 25
H= Holding Cost = 0.05
[tex]Q_{opt} = \sqrt{\frac{2DS}{H}}[/tex]
[tex]Q_{opt} = \sqrt{\frac{2(25,000)(25)}{0.05}}[/tex]
EOQ = 5,000
EDIT: there is insufficient information to solve the third question as the previous scenario wasn't attached.