You and your friend are making 30 liters of sodium water. You have liters of 10% sodium and your friend has liters of 22% sodium. How many of your liters and how many of your friends liters should you mix to make 30 liters of 15% sodium?

x liters of 10% + (30 - x) liters of 22% = 30 liters of 15%

Plugging in the numbers
x(10) + (30 - x)22 = 30(15)

Distribute
10x + 660 - 22x = 450

Combine like terms
-12x = -210

Divide both sides by -12
x = 17.5
30 - x = 12.5

17.5 liters of 10% + 12.5 liters of 22% = 30 liters of 15%

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lublana lublana · Answer 2 · 2019-12-19T05:58:38+01:00

Answer:

You have 17.5 liters of 10% sodium and your friend has 12.5 liters of 22% .

Step-by-step explanation:

We are given that

Total sodium water=30 L

Let you have sodium water=x of 10%

Your friend has sodium water =(30-x) of 22%

We have to find that how many of your liters and your friend liters should you mix to make 30 liters of 15% sodium.

According to question

x of 10%+(30-x) of 22%=30 of 15%

[tex]\frac{x\times 10}{100}+(30-x)\times \frac{22}{100}=30\times \frac{15}{100}[/tex]

[tex]\frac{10x}{100}+\frac{660-22x}{100}=\frac{450}{100}[/tex]

[tex]\frac{10x-22x+660}{100}=\frac{450}{100}[/tex]

[tex]\frac{-12x+660}{100}=\frac{450}{100}[/tex]

Multiply by 100 on both sides then, we get

[tex]-12x+660=450[/tex]

[tex]660-450=12x[/tex]

[tex]12x=210[/tex]

[tex]x=\frac{210}{12}=17.5[/tex]

You have 17.5 liters of 10% sodium

Your friend has liters of 22% sodium=30-17.5=12.5 L