Respuesta :
fo a circle with radius, r and center (h,k)
te equation is
(x-h)²+(y-k)²=r²
d/2=r
8/2=4=r
center is (-2,-3)
(x-(-2))²+(y-(-3))²=4²
(x+2)²+(y+3)²=16
te equation is
(x-h)²+(y-k)²=r²
d/2=r
8/2=4=r
center is (-2,-3)
(x-(-2))²+(y-(-3))²=4²
(x+2)²+(y+3)²=16
Answer:
Equation of circle is (x + 2) ²+ ( y + 3)² = 4².
Step-by-step explanation:
Given : a circle with a center at (-2,-3) and a diameter of 8 units.
To find : Which equation represents the general form of a circle .
Solution : We have given center at (-2,-3) and a diameter of 8 units.
Radius = [tex]\frac{Diameter}{2}[/tex].
Radius = [tex]\frac{8}{2}[/tex].
Radius = 4 units.
Standard form of circle is (x -h) ²+ ( y -k)² = r².
Where, ( h, k) is center , r = radius .
Plug center ( -2 ,-3) and r = 4 .
(x - (-2)) ²+ ( y - (-3))² = 4².
(x + 2) ²+ ( y + 3)² = 4².
Therefore, Equation of circle is (x + 2) ²+ ( y + 3)² = 4².