contestada

Which equation represents the general form of a circle with a center at (-2,-3) and a diameter of 8 units

Respuesta :

fo a circle with radius, r and center (h,k)
te equation is
(x-h)²+(y-k)²=r²
d/2=r
8/2=4=r
center is (-2,-3)

(x-(-2))²+(y-(-3))²=4²
(x+2)²+(y+3)²=16

Answer:

Equation of circle is  (x + 2) ²+ ( y + 3)² = 4².

Step-by-step explanation:

Given  : a circle with a center at (-2,-3) and a diameter of 8 units.

To find : Which equation represents the general form of a circle .

Solution : We have given  center at (-2,-3) and a diameter of 8 units.

Radius = [tex]\frac{Diameter}{2}[/tex].

Radius =  [tex]\frac{8}{2}[/tex].

Radius = 4 units.

Standard form of circle is  (x -h) ²+ ( y -k)² = r².

Where,  ( h, k) is center , r =  radius .

Plug center ( -2 ,-3) and  r = 4 .

 (x - (-2)) ²+ ( y - (-3))² = 4².

 (x + 2) ²+ ( y + 3)² = 4².

Therefore, Equation of circle is  (x + 2) ²+ ( y + 3)² = 4².