ginazarza ginazarza

23-10-2016
Chemistry

contestada

as a step O3 0.020 mol to gr

Respuesta :

Willchemistry Willchemistry

23-10-2016

Molar mass:

Atomic mass O = 16.0 a.m.u

O₃ = 16.0 x 3 => 48.0 g/mol

Therefore:

1 mole O₃ --------------- 48.0 g
0.020 mole O₃ ---------- ??

0.020 x 48.0 / 1 =

0.96 / 1 => 0.96 g

hope this helps!

Answer Link

Otras preguntas

Andrew Johnson was charged with breaking the Tenure of Office Act of 1867 for refusing to appoint a new vice president after he assumed the office of president.

Every sponsible search for rental property will include all of the following except A. A careful search of available properties using newspapers finder service

Select the correct spelling below. Endeavor Endeavour Endevore endevore

Find the x intercept of the parabola with vertex (1,20) and u intercept (0,16). Write answer in form (X1,y2)(x2,y2)

which not a factor of 72 A 16 B 18 C 24 D 36

Which of these steps is crucial when doing a close reading of nonfiction? scanning the text for information writing notes in the margins summarizing the text cr

conclusion drawn from school rule and regulation

PLEASE HELP FAST !!!!! PLEASEEEEEEEE The cost of go-karting is dollars for the first ten laps around the track and dollars for each additional lap. What is th

The word when is a verb. TRUE or FALSE.

Select the correct answer. Which of the following structures represents the sporophyte stage of the bryophytes? protonema antheridia capsule NextReset