Answer:
Factors are (2a+b) and (5x-4y)
Option D is correct.
Step-by-step explanation:
Given: [tex]10ax+5bx-8ay-4by[/tex]
Here we are four term to factor it.
First we make two group and factor each group.
[tex](10ax+5bx) + (-8ay-4by)[/tex]
[tex]\text{Group 1: }10ax+5bx[/tex]
Taking 5x common from both term
[tex]10ax+5bx\Rightarrow 5x(2a+b)[/tex]
[tex]\text{Group 2: }-8ay-4by[/tex]
Taking -4y common from both term
[tex]-8ay-4by\Rightarrow -4y(2a+b)[/tex]
Factor is:
[tex]\Rightarrow 5x(2a+b)-4y(2a+b)[/tex]
[tex]\Rightarrow (2a+b)(5x-4y)[/tex]
Hence, Factors are (2a+b) and (5x-4y)
