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emmarobert
In the equation y=mx+b, 'm' is the slope of the line and 'b' is the y-intercept.  
First, you should find the slope of the line.  To do this, use the equation M=y2-y1/x2-x1.  Using the two given points (3,6) and (8,4), you can solve for M.  
M=4-6/8-3
M=-2/5 (-0.4 in decimal form)
Now, your equation is y=-0.4x+b
Next you must solve for b to find the y-intercept.  You can do this by subbing one of the given points in for x and y.  
Using the point (3,6):
y=-0.4x+b
6=-0.4(3)+b
6=-1.2+b
Isolate b:
6+1.2=b
b=7.2
And now you have the equation of the line!
y=-0.4x+7.2 (IN FRACTION FORM: y=-2/5x+36/5)
abidemiokin

The equation of the line that passes through the points (3, 6) and (8,4)  is 5y + 2x  = 36

The standard equation of a line is expressed as y = mx + b where;

m is the slope of the line

b is the y-intercept

Given the coordinate points (3, 6) and (8, 4)

Get the slope "m"

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{4-6}{8-3}\\m=\frac{-2}{5}[/tex]

Get the y-intercept;

Recall that y = mx + b

6 = -2/5(3) + b

6 = -6/5 + b

b = 6 + 6/5

b = 36/5

Get the required equation

y = -2/5x + 36/5

Multiply through by 5

5y = -2x + 36

5y + 2x = 36

Hence the equation of the line that passes through the points (3, 6) and (8,4)  is 5y + 2x  = 36

Learn more here: https://brainly.com/question/17003809

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