Respuesta :
y=5x-1
-15x-3y=3
-15x-15x+3=3
-30x=0
x=0
therefore y=5x0 -1= -1
so one solution(0,-1)
-15x-3y=3
-15x-15x+3=3
-30x=0
x=0
therefore y=5x0 -1= -1
so one solution(0,-1)
Answer:
Option 1 - There is one solution : (0,-1)
Step-by-step explanation:
Given : The system of equations [tex]y=5x-1[/tex] and [tex]-15x-3y=3[/tex]
To find : How many solutions does this linear system have?
Solution :
Let Equation (1), [tex]y=5x-1[/tex]
Equation (2), [tex]-15x-3y=3[/tex]
Applying substitution method,
Substitute y from equation (1) into (2),
[tex]-15x-3y=3[/tex]
[tex]-15x-3(5x-1)=3[/tex]
[tex]-15x-15x+3=3[/tex]
[tex]-30x=0[/tex]
[tex]x=0[/tex]
Substitute in equation (1),
[tex]y=5x-1[/tex]
[tex]y=5(0)-1[/tex]
[tex]y=-1[/tex]
Therefore, There is one solution : (0,-1)
So, Option 1 is correct.
