Respuesta :
Let x units be the length of the shortest side of the triangle.
Perimeter of triangle = 2(x + 1) +x = 3x + 2
Perimeter of square = 4(x - 2) = 4x - 8
Equating the two expressions for perimeters, we get:
3x + 2 = 4x - 8
The solution is: x = 10
The answer is 10 units.
Perimeter of triangle = 2(x + 1) +x = 3x + 2
Perimeter of square = 4(x - 2) = 4x - 8
Equating the two expressions for perimeters, we get:
3x + 2 = 4x - 8
The solution is: x = 10
The answer is 10 units.