Respuesta :
3) we calculate the second derivative:
C´´(x)=-0.6; because -0.6>0; we have a maximun at x=1000.
4)We find out the maximum cost.
C(1000)=600(1000)-0.3(1000)²
C(1000)=600000-300000
C(1000)=300000
so the answer is (x)=-0.6;
C´´(x)=-0.6; because -0.6>0; we have a maximun at x=1000.
4)We find out the maximum cost.
C(1000)=600(1000)-0.3(1000)²
C(1000)=600000-300000
C(1000)=300000
so the answer is (x)=-0.6;