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The probability that Roberto throws a baseball in the strike zone on one pitch is 0.72. Roberto throws a baseball 3 times in a row.
A. Create a probability distribution for X, the number of times Roberto throws the baseball in the strike zone. Show how you obtained each probability. Round each probability to three decimal places.

Respuesta :

roo777x
I actually just finished this assignment: 

These are binomials with n = 3 and p = 0.72

P(X=0) = 3C0 (0.72^0)(0.28^3) = 0.022
P(X=1) = 3C0 (0.72^1)(0.28^2) = 0.169
P(X=2) = 3C0 (0.72^2)(0.28^1) = 0.435
P(X=3) = 3C0 (0.72^3)(0.28^0) = 0.373 

Notice how they all equal 1.

shristiparmar1221

This question is based on probability distribution. Therefore, the probability distribution for X are ,P(X=0) = 0.022 ,P(X=1) = 0.169, P(X=2) = 0.435 and P(X=3) = 0.373.

Given:

The probability that Roberto throws a baseball in the strike zone on one pitch is 0.72. Roberto throws a baseball 3 times in a row.

We need to determined the probability distribution for X ,the number of times Roberto throws the baseball in the strike zone.

According to the question,

By using the combination formula, we have to solve it,

It is given that n = 3 and p = 0.72.

Now calculating the P(X=0), we get,

[tex]P(X=0) = 3_{C_0}(0.72)^0(0.28)^3 \\P(X=0) = 0.022[/tex]

Now calculating the P(X=1), we get,

[tex]P(X=1) = 3_{C_0}(0.72)^1(0.28)^2 \\P(X = 1)= 0.169[/tex]

Now calculating the P(X=2), we get,

[tex]P(X=2) = 3_{C_0} (0.72)^2(0.28)^1 \\P(X=2) = 0.435[/tex]

Now calculating the P(X=3), we get,

[tex]P(X=3) = 3_{C_0} (0.72)^3(0.28)^0\\P(X=3) = 0.373[/tex]

Therefore, the probability distribution for X are ,P(X=0) = 0.022 ,P(X=1) = 0.169, P(X=2) = 0.435 and P(X=3) = 0.373.

For more details, prefer this link:

https://brainly.com/question/14210034

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