Respuesta :

bcalle
Since 121 is a perfect square, 12x12, and 49 is a perfect square, 7x7, and b^4 is a perfect square, b^2xb^2, you have what's called the difference of perfect squares. These factor into the sum and difference of the square roots. So (11b^2+7)(11b^2-7)

Answer:

The factorization of the expression is [tex]121b^4-49=(11b-7)(11b+7)[/tex]

Step-by-step explanation:

Given : Expression [tex]121b^4-49[/tex]

To find : What is the factorization of given expression?

Solution :

Expression [tex]121b^4-49[/tex]

Using algebraic identity,

[tex]x^2-y^2=(x+y)(x-y)[/tex]

Making the term in square form,

[tex]121b^4=(11b)^2[/tex]

[tex]49=7^2[/tex]

So,  [tex]121b^4-49=(11b)^2-7^2[/tex]

Applying property,

[tex]121b^4-49=(11b-7)(11b+7)[/tex]

Therefore, The factorization of the expression is [tex]121b^4-49=(11b-7)(11b+7)[/tex]

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