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Consider an electron within the 1s orbital of a hydrogen atom. the normalized probability of finding the electron within a sphere of a radius r centered at the nucleus is given by

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What is the probability of finding an electron within one Bohr radius of the nucleus?Consider an electron within the 1s orbital of a hydrogen atom. The normalized probability of finding the electron within a sphere of a radius R centered at the nucleus is given by 1-a0^2[a0^2-e^(-2R/a0)(a0^2+2a0R+2R2)]. Where a0 is the Bohr radius (for a hydrogen atom, a0 = 0.529 Å.). What is the probability of finding an electron within one Bohr radius of the nucleus? What is the probability of finding an electron of the hydrogen atom within a 2.30a0 radius of the hydrogen nucleus?

Below is the answer:

you plug the values for A0 and R into your formula
zohazoee

Answer:

the normalized probability of finding the electron within sphere of a radius r centered at the nucleus is given by:

Normalized probability =  [tex]1/ a_{0} ^2[a_{0} ^2-e^2^r^/^a_{} (a_{0} ^2+2a_{0} r+2r^2)][/tex]

where [tex]a_{0}[/tex] is Bohr radius ( for a hydrogen atom [tex]a_{0} =0.529 A[/tex]

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