Respuesta :
When answering the above question or problem, first thing to realize is that the dissolution of the Na3PO4 can be written in a format that may be easier to see what is happening here.
Na3PO4 ----> 3 Na(+) + PO4(-3)
Now, you are starting out with a 0.35 M solution of Na3PO4, but when you dissolve the Na3PO4 into solution there are 3 Na(+) ions made for every Na3PO4 molecule that dissolves. Therefore to calculate the concentration of Na(+) ions in the final solution, take 3 times the inital concentration. 0.35 * 3 = 1.05 M in Na(+)
Na3PO4 ----> 3 Na(+) + PO4(-3)
Now, you are starting out with a 0.35 M solution of Na3PO4, but when you dissolve the Na3PO4 into solution there are 3 Na(+) ions made for every Na3PO4 molecule that dissolves. Therefore to calculate the concentration of Na(+) ions in the final solution, take 3 times the inital concentration. 0.35 * 3 = 1.05 M in Na(+)
Answer : The molar concentration of phosphate ions in lithium phosphate solution is, 0.350 M
Explanation : Given,
Concentration of lithium phosphate = 0.350 M
As lithium phosphate dissolve in water, it dissociates into lithium ions and phosphate ions.
The balanced reaction will be,
[tex]Li_3PO_4\rightarrow 3Li^++PO_4^{3-}[/tex]
From the balanced reaction we conclude that,
As, mole ratio of [tex]Li_3PO_4[/tex], [tex]Li[/tex] and [tex]PO_4^{3-}[/tex] is, 1 : 3 : 1
So,
The molar concentration of lithium ion = 3 × 0.350 M = 1.05 M
The molar concentration of phosphate ion = 0.350 M
Therefore, the molar concentration of phosphate ion is, 0.350 M