Respuesta :

easey
f(x)=ax^2+bx+c
leading coefient is a
f(x)=1x^2-8x-4
leading coefient is 1

Answer:

The answer is

the value of the leading coefficient is equal to [tex]1[/tex]

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]f(x)=x^{2} -8x-4[/tex]  

equate the function to zero

[tex]x^{2} -8x-4=0[/tex]    

so

[tex]a=1\\b=-8\\c=-4[/tex]

the value of the leading coefficient is equal to a

[tex]a=1[/tex]