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14. The load across a 50.0-V battery consists of a
series combination of two lamps with resistances of
125 Q2 Land 225 22.
a. Find the total resistance of the circuit.
b. Find the current in the circuit.
c. Find the potential difference across the
125-12 lamp

Respuesta :

asuwafohjames

(a) The total resistance of the circuit is 350 ohms

(b) The total current in the circuit is 0.143 A

(c) The potential difference across the 125-Ω lamp is 17.875 V.

What is resistance?

Resistance can be defined as the opposition to the flow of current in an electric circuit.

(a) To calculate the total resistance of the circuit, we use the series combination formula:

Formula:

  • R' = R₁+R₂............ Equation 1

Given:

  • R' = Total resistance of the circuit
  • R₁ = 125 ohms
  • R₂ = 225 ohms

Substitute these values into equation 1

  • R' = 125+225
  • R' = 350 ohms

(b) To find the current in the circuit, we use the formula below.

Formula:

  • I = V/R'............ Equation 2

Where:

  • I = current in the circuit
  • V = Voltage of the battery
  • R' = Total  resistance of the circuit

Given:

  • V = 50 V
  • R' = 350 ohms

Substitute these values into equation 2

  • I = 50/350
  • I = 0.143 A

(c) To calculate the potential difference across the 125-Ω lamp, we use the formula below

  • V₁ = IR₁......... Equation 3

Where:

  • V₁ = Potential difference across the 125-Ω
  • I = 0.143 A
  • R₁ = 125

Substitute these values into equation 3

  • V₁ = 125×0.143
  • V₁ = 17.875 V

Hence, (a) The total resistance of the circuit is 350 ohms (b) The total current in the circuit is 0.143 A (c) The potential difference across the 125-Ω lamp is 17.875 V.

Learn more about resistance here: https://brainly.com/question/26516520

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