what linear equation in slope intercept from does this graph represent?

Answer:
[tex]y = 16\frac{2}{3} x + 100[/tex] or [tex]y = \frac{50}{3} + 100[/tex]
Step-by-step explanation:
The equation of a line is [tex]y = mx + b[/tex], with [tex]m[/tex] being the slope and [tex]b[/tex] being the y-intercept.
We can see on the graph that the y-intercept, where the line crosses or touches the y-axis, is 100. So, our new equation is [tex]y = mx + 100[/tex].
Now we have to find the slope. Let's pick a point that's clearly on the graph. Perhaps (3, 150). And then we'll take the y-intercept point for convenience, (0, 100).
Then, we'll use [tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1} }[/tex] to find the slope.
Let's substitute in our points.
[tex]\frac{150-100}{3-0}[/tex]
Simplify.
[tex]\frac{50}{3}[/tex]
Now, we can leave the slope like that or turn it into a mixed number. As a mixed number, your slope is [tex]16\frac{2}{3}[/tex].
We'll put that in our equation for a line and...bam!
[tex]y = 16\frac{2}{3} x + 100[/tex] or [tex]y = \frac{50}{3} + 100[/tex]