Answer:
700 Hz
Explanation:
From the given information;
If we consider the formula for the frequency of an open-end tube; we have the formula:
[tex]f_{op} = \dfrac{v}{2L}[/tex]
For a closed-end tube;
[tex]f_{closed}= \dfrac{v}{4L}[/tex]
However, the fundamental frequency of open end tube can be expressed as:
[tex]f_{op} = 2( \dfrac{v}{4L})[/tex]
where;
[tex]f_{closed}= \dfrac{v}{4L}[/tex]
Then; the fundamental frequency of the open end tube is:
[tex]f_{op} = 2( f_{closed})[/tex]
[tex]f_{op[/tex] = 2(350)
[tex]f_{op[/tex] = 700 Hz
The fundamental frequency for the open end tube is 700 Hz.
Given data:
The fundamental frequency of sound for open end tube is, f'= 350 Hz.
By using the formula for the frequency of an open-end tube; we have the formula:
f = v/2L .......................................(1)
Here,
v is the speed of sound wave.
L is the length of given tube.
For a closed-end tube, the fundamental frequency is given as,
f' = v/4L ............................................(2)
And the fundamental frequency of open end tube can be expressed as,
f'' = 2 (v/4L)
Substitute the value of equation (2) as,
f'' = 2 (f')
Solving as,
f'' = 2 (350)
f'' = 700 Hz.
Thus, we can conclude that the fundamental frequency for the open end tube is 700 Hz.
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