Answer:
The probability is ⁹/₆₄
Step-by-step explanation:
Given;
number of red marbles, R = 3
number of green marbles, G = 5
Total number of marbles, T = 8
The probability of choosing two red marbles in a row with replacement;
[tex]P(2 R) = P(R_1 \ n \ R_2)\\\\P(2 R) = \frac{3}{8} \ \times \ \frac{3}{8} \\\\P(2 R) = \frac{9}{64}[/tex]
Therefore, the probability of choosing two red marbles in a row with replacement is ⁹/₆₄
