The equation of the line that passes through the point(1, 3) and is perpendicular to the line 2x + 3y = 15 is y = 3 / 2x + 3 / 2.
How to find the equation of a line perpendicular to another?
The line passing through (1, 3) is perpendicular to the equation 2x+3y=15.
Therefore,
y = mx + b
where
Hence,
3y = -2x + 15
y = -2 / 3 x + 5
For line to be perpendicular it must follow the following rules;
m₁m₂ = -1
m₁(-2 / 3) = -1
-2m₁ = -3
m₁ = 3 / 2
Therefore, the equation can be found as follows:
3 = 3 / 2(1) + b
3 = 3 / 2 + b
b = 3 - 3 / 2
b = 6 - 3 / 2
b = 3 / 2
Hence,
y = 3 / 2x + 3 / 2
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