Answer:
less=−5
greater=−1
step by step:
/ 3
\begin{aligned} (x + 3)^2 - 4 &= 0 \\\\ (x+3)^2&=4 \\\\ \sqrt{(x+3)^2}&=\sqrt{4} \end{aligned}
(x+3)
2
−4
(x+3)
2
(x+3)
2
=0
=4
=
4
Hint #22 / 3
\begin{aligned} x+3&=\pm2 \\\\ x&=\pm2-3 \\ \phantom{(x + 3)^2 - 4}& \\ x=-5&\text{ or }x=-1 \end{aligned}
x+3
x
(x+3)
2
−4
x=−5
=±2
=±2−3
or x=−1
Hint #33 / 3
In conclusion,
\begin{aligned} \text{lesser }x &= -5 \\\\ \text{greater } x &= -1 \end{aligned}
lesser x
greater x
=−5
=−1
Answer:
I dont know
Step-by-step explanation:
But just read that guys answer he is right.
