Answer:
[tex]\huge\boxed{y=5-\frac{2}{3}x}[/tex]
Step-by-step explanation:
With the equation [tex]\displaystyle 2x+3y=15[/tex], we can solve for y by algebraically manipulating the question until we have y isolated on one side.
It's important to note that if we do something to one side, we have to do it to another. Just as [tex]5=5[/tex], adding two to both sides still makes it true [tex]5+2=5+2, 7=7[/tex].
- [tex]2x+3y=15[/tex]
- [tex]\displaystyle \frac{2x}{3} + \frac{3y}{3} = \frac{15}{3}[/tex]
- [tex]\displaystyle \frac{2}{3}x+y=5[/tex]
- [tex]\displaystyle \frac{2}{3}x - \frac{2}{3}x +y=5 - \frac{2}{3}x[/tex]
- [tex]\displaystyle y = 5 - \frac{2}{3}x[/tex]
Therefore, this equation for y is [tex]\displaystyle y = 5 - \frac{2}{3}x[/tex] .
Hope this helped!
