Students who attend Anytown College pay either in-state or out-of-state tuition, depending on where they reside. The amount, I, spent on in-state tuition for a randomly selected student has a mean of $2,523.75 and a standard deviation of $1,003.25. The amount, O, spent on out-of-state tuition for a randomly selected student has a mean of $3,825.00 and a standard deviation of $1,126.50.

Suppose we randomly select one student who pays in-state tuition and one student who pays out-of-state tuition.

Calculate the mean of the sum S = I + O.

μS = $227.69
μS = $1,301.25
μS = $1,508.48
μS = $6,348.75

Respuesta :

Answer:

6,348.75

Step-by-step explanation:

Just add the means. It’s right, just did it!

Using statistical concepts, it is found that the mean of the sum S = I + O is of:

[tex]\mu_S = 6348.75[/tex]

What happens when two variables are added?

  • When two variables are added, the mean is the sum of the means, while the standard deviation is the square root of the sum of the variances.

In this problem:

  • The mean of I is of [tex]\mu_I = 2523.75[/tex].
  • The mean of O is of [tex]\mu_O = 3825.00[/tex].

S is the sum of I and O, hence:

[tex]\mu_S = \mu_I + \mu_O = 2523.75 + 3825.00 = 6348.75[/tex]

You can learn more about operations with variables at https://brainly.com/question/26156502