Answer:
Let's define:
C = number of children tickets bought
A = number of adult tickets bought.
We know that "On a certain day, if 14 times as many children's tickets were bought as adult meal tickets"
Then we have:
C = 14*A
And we also know that:
"the total revenue from selling all tickets was $2,584"
Then:
C*$4 + A*$9 = $2,584
Then we have a system of equations:
C = 14*A
C*$4 + A*$9 = $2,584
The first step to solve these is to isolate one of the variables in one of the equations, and then replacing it in the other equation. We can already see that C is already isolated in the first equation, then we can just replace it in the second one to get:
(14*A)*$4 + A*$9 = $2,584
A*$56 + A*$9 = $2,584
A*$65 = $2,584
A = $2,584/$65 = 39.75
Here we should have a whole number, (So one of the numbers given may be incorrect) This is because we can not have a 0.75 of a ticket sold.
In this case, we know that:
C = A*14
C = 39.75*14 = 546.5
We could round this up to get a whole number; 547
About 547 children tickets were sold.
