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An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance does the object move while accelerating?
A) 30 m
B) 3 m
C) 90 m
D) 600 m

Respuesta :

Answer:

Distance s  = 90 meter

Explanation:

Given:

Initial velocity u = 0 m/s

Final velocity v = 30 m/s

Acceleration a = 5 m/s²

Find:

Distance s

Computation:

v² = u² + 2as

30² = 0² + 2(5)(s)

Distance s  = 90 meter

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