Answer:
The distance of two complex numbers
[tex]z_{1} z_{2} = \sqrt{82}[/tex] = 9.055
Step-by-step explanation:
Step(i):-
Given that z₁ = 6-3i and z₂ = -3-4i
We know that 'z' represents a point on the argand plane with absicca 'x' and ordinate 'y'
Now given points are ( x₁ , y₁) = (6 ,-3) and (x₂, y₂) = (-3 , -4)
Step(ii):-
The distance of two points
[tex]\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} - y_{1} )^{2} }[/tex]
z₁ z₂ [tex]= \sqrt{(-3-6)^{2} +(-4-(-3)^{2} }[/tex]
[tex]z_{1} z_{2} = \sqrt{81+1}[/tex]
[tex]z_{1} z_{2} = \sqrt{82}[/tex] =9.055
