Answer:
x = -3 ; y = -1
Step-by-step explanation:
Let 9x - 6y = -21 be eqn.1 & let 6x - 12y = -6 be eqn.2 .
Lets find the value of x from eqn.1
[tex]9x - 6y= -21[/tex]
[tex]=> 3(3x - 2y) = -21[/tex]
[tex]=> 3x - 2y = \frac{-21}{3} = -7[/tex]
[tex]=> x = \frac{2y - 7}{3}[/tex]
Now , lets put the value of x (which we got from eqn.1) in eqn.2 :-
[tex]6x - 12y = -6[/tex]
[tex]=> 6(x - 2y) = -6[/tex]
[tex]=> x - 2y = \frac{-6}{6} = -1[/tex]
(Putting x here)
[tex]=> \frac{2y - 7}{3} - 2y = -1[/tex]
[tex]=> \frac{2y - 7 - 6x}{3} = - 1[/tex]
[tex]=> -4 y - 7 = -1 \times 3 = -3[/tex]
[tex]=> -4y = 7 - 3 = 4[/tex]
[tex]=> y = \frac{-4}{4} = -1[/tex]
Now , lets find the value of x.
[tex]x = \frac{2y - 7}{3}[/tex]
Putting y = -0.5 gives ,
[tex]x = \frac{[2 \times (-1)] - 7}{3}[/tex]
[tex]=> x = \frac{-2 - 7}{3} = \frac{-9}{3} = -3[/tex]
