Can someone please help

Answer:
The equation of the line is:
Step-by-step explanation:
The slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where
Given the points
Determining the slope between (0, 1) and (4, -2)
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:-2\right)[/tex]
[tex]m=\frac{-2-1}{4-0}[/tex]
Refine
[tex]m=-\frac{3}{4}[/tex]
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
As
The point (0, 1) is given.
It means at x = 0, the vaule of y = 1
Thus, the y-intercept b = 1
now substituting m = -3/4 and b = 1 in the slope-intercept form of line equation
y = mx+b
y = -3/4x + 1
Therefore, the equation of the line is: