Answer:
F' = 162 units
Explanation:
The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:
[tex]F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\[/tex]
where,
F = gravitational force = 18 units
G = Gravitational Constant
m₁ = mass of object 1
m₂ = mass of object 2
r = distance between objects
Therefore,
[tex]18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\[/tex]
Now, if we change the value of distance to one-third of original value, then:
r' = r/3
[tex]F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})[/tex]
using eqn (1):
F' = 9(18 units)
F' = 162 units
